Assume that there are 5 different issues of Popular Science, 4 different issues of Time, and 2 different issue?

Assume that there are 5 different issues of Popular Science, 4 different issues of Time, and 2 different issues of Newsweek, including the December 1st issue, on the rack. You choose 4 of them at random.

(1) What is the probability that you choose 1 issue of Popular Science and 3 issues of Time?



(2) What is the probability that you choose at least 3 of the Time magazines?Assume that there are 5 different issues of Popular Science, 4 different issues of Time, and 2 different issue?
q1

[5 pop sc, choose 1]*

[4 time, choose 3] /

[11 total, choose 4]



= 5c1*4c3 /11c4 = 20/330

= 2/33

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q2

{3 time, 1 other} + (4 time}

(4c3*7c1 + 4c4)/11c4

= 29/330

------------Assume that there are 5 different issues of Popular Science, 4 different issues of Time, and 2 different issue?
There are 11 Magazine in all.

1. the probability that you pick a Popular Science is 5/11.

the probability that you pick the first Time is 4/10 which reduces to 2/5

the probability that you pick the second Time is 3/9 which reduces to 1/3

the probability that you pick the third Time is 2/8 which reduces to 1/4

Then you multiply them together like so:

5/11 * 2/5 * 1/3 * 1/4



So then the answer would be:

10/660 which reduces to 1/66

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